$[2000,06]$
(a) $3.4 nm$
(b) $2 nm$
(c) $0.34 nm$
(d) $20 nm$
(a) Length of one turn of DNA helix is $34 \AA$. $1 \AA=10^{-1} nm$ $ \therefore 34^{-}=10^{-1} \times 34=\frac{34 \times 1}{10}=3.4 nm $
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