Work Power Energy Question 7
Question 7 - 2024 (30 Jan Shift 1)
A particle is placed at the point $A$ of a frictionless track $ABC$ as shown in figure. It is gently pushed toward right. The speed of the particle when it reaches the point B is : $\left(\right.$ Take $\left.g=10 m / s^{2}\right)$.
(1) $20 m / s$
(2) $\sqrt{10} m / s$
(3) $2 \sqrt{10} m / s$
(4) $10 m / s$
Show Answer
Answer: (2)
Solution:
By COME
$KE _A+U _A=KE _B+U _B$
$0+\operatorname{mg}(1)=\frac{1}{2} mv^{2}+mg \times 0.5$
$v=\sqrt{g}=\sqrt{10} m / s$
