Nuclear Physics Question 8
Question 8 - 2024 (31 Jan Shift 2)
A nucleus has mass number $A _1$ and volume $V _1$. Another nucleus has mass number $A _2$ and volume $V _2$. If relation between mass number is $A _2=4 A _1$, then $\frac{V _2}{V _1}=$
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Answer: (4)
Solution:
For a nucleus
Volume: $V=\frac{4}{3} \pi R^{3}$
$R=R _0(A)^{1 / 3}$
$V=\frac{4}{3} \pi R _0^{3} A$
$\Rightarrow \frac{V _2}{V _1}=\frac{A _2}{A _1}=4$
