Nuclear Physics Question 8
Question 8 - 2024 (31 Jan Shift 2)
A nucleus has mass number $A_{1}$ and volume $V_{1}$. Another nucleus has mass number $A_{2}$ and volume $V_{2}$. If relation between mass number is $A_{2}=4 A_{1}$, then $\frac{V_{2}}{V_{1}}=$
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Answer: (4)
Solution:
For a nucleus
Volume: $\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^{3}$
$\mathrm{R}=\mathrm{R}_{0}(\mathrm{~A})^{1 / 3}$
$\mathrm{V}=\frac{4}{3} \pi \mathrm{R}_{0}^{3} \mathrm{~A}$
$\Rightarrow \frac{\mathrm{V}{2}}{\mathrm{~V}{1}}=\frac{\mathrm{A}{2}}{\mathrm{~A}{1}}=4$
