The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is:
(1) 24
(2) 32
(3) 40
(4) 20
$R _1=\frac{R _2}{2}$
$R _0\left(A _1\right)^{1 / 3}=\frac{R _0}{2}\left(A _2\right)^{1 /}$
$A _1=\frac{1}{8} A _2$
$A _1=\frac{192}{8}=24$
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