Magnetic Effects Of Current Question 7
Question 7 - 2024 (29 Jan Shift 1)
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of $20 cm$ from its center is $1.5 \times 10^{-5} Tm$. The magnetic moment of the dipole is $Am^{2}$. (Given : $\frac{\mu _0}{4 \pi}=10^{-7} TmA^{-1}$ )
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Answer: (6)
Solution:
$V=\frac{\mu _0}{4 \pi} \frac{M}{r^{2}}$
$\Rightarrow 1.5 \times 10^{-5}=10^{-7} \times \frac{M}{\left(20 \times 10^{-2}\right)^{2}}$
$\Rightarrow M=\frac{1.5 \times 10^{-5} \times 20 \times 20 \times 10^{-4}}{10^{-7}}$
$M=1.5 \times 4=6$
