Magnetic Effects Of Current Question 7
Question 7 - 2024 (29 Jan Shift 1)
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of $20 \mathrm{~cm}$ from its center is $1.5 \times 10^{-5} \mathrm{Tm}$. The magnetic moment of the dipole is $\mathrm{Am}^{2}$. (Given : $\frac{\mu_{0}}{4 \pi}=10^{-7} \mathrm{TmA}^{-1}$ )
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Answer: (6)
Solution:
$\mathrm{V}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{M}}{\mathrm{r}^{2}}$
$\Rightarrow 1.5 \times 10^{-5}=10^{-7} \times \frac{\mathrm{M}}{\left(20 \times 10^{-2}\right)^{2}}$
$\Rightarrow \mathrm{M}=\frac{1.5 \times 10^{-5} \times 20 \times 20 \times 10^{-4}}{10^{-7}}$
$\mathrm{M}=1.5 \times 4=6$
