Current Electricity Question 19
Question 19 - 2024 (30 Jan Shift 1)
Two cells are connected in opposition as shown. Cell $E _1$ is of $8 V$ emf and $2 \Omega$ internal resistance; the cell $E _2$ is of $2 V$ emf and $4 \Omega$ internal resistance. The terminal potential difference of cell $E _2$ is:
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Answer: (6)
Solution:
$I=\frac{8-2}{2+4}=\frac{6}{6}=1 A$
Applying Kirchhoff from C to B
$V _C-2-4 \times 1=V _B$
$V _C-V _B=6 V$
$=6 V$
