Current Electricity Question 19
Question 19 - 2024 (30 Jan Shift 1)
Two cells are connected in opposition as shown. Cell $\mathrm{E}{1}$ is of $8 \mathrm{~V}$ emf and $2 \Omega$ internal resistance; the cell $\mathrm{E}{2}$ is of $2 \mathrm{~V}$ emf and $4 \Omega$ internal resistance. The terminal potential difference of cell $\mathrm{E}_{2}$ is:
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Answer: (6)
Solution:
$I=\frac{8-2}{2+4}=\frac{6}{6}=1 \mathrm{~A}$
Applying Kirchhoff from C to B
$V_{C}-2-4 \times 1=V_{B}$
$V_{C}-V_{B}=6 \mathrm{~V}$
$=6 \mathrm{~V}$
