Binomial Theorem Question 8
Question 8 - 2024 (30 Jan Shift 1)
Number of integral terms in the expansion of ${7^{\left(\frac{1}{2}\right)}+11^{\left(\frac{1}{6}\right)} }^{824}$ is equal to
Show Answer
Answer (138)
Solution
General term in expansion of $\left((7)^{1 / 2}+(11)^{1 / 6}\right)^{824}$ is
$t _{r+1}={ }^{824} C _r(7)^{\frac{824-r}{2}}(11)^{r / 6}$
For integral term, $r$ must be multiple of 6 .
Hence $r=0,6,12$,
