Binomial Theorem Question 8
Question 8 - 2024 (30 Jan Shift 1)
Number of integral terms in the expansion of $\left{7^{\left(\frac{1}{2}\right)}+11^{\left(\frac{1}{6}\right)}\right}^{824}$ is equal to
Show Answer
Answer (138)
Solution
General term in expansion of $\left((7)^{1 / 2}+(11)^{1 / 6}\right)^{824}$ is
$t_{\mathrm{r}+1}={ }^{824} \mathrm{C}_{\mathrm{r}}(7)^{\frac{824-\mathrm{r}}{2}}(11)^{\mathrm{r} / 6}$
For integral term, $r$ must be multiple of 6 .
Hence $r=0,6,12$,
