Binomial Theorem Question 7
Question 7 - 2024 (29 Jan Shift 2)
Remainder when $64^{32^{32}}$ is divided by 9 is equal to
Show Answer
Answer (1)
Solution
Let $32^{32}=t$
$64^{32^{32}}=64^{t}=8^{2 t}=(9-1)^{2 t}$
$=9 k+1$
Hence remainder $=1$
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