Remainder when $64^{32^{32}}$ is divided by 9 is equal to
Let $32^{32}=\mathrm{t}$
$64^{32^{32}}=64^{\mathrm{t}}=8^{2 \mathrm{t}}=(9-1)^{2 \mathrm{t}}$
$=9 \mathrm{k}+1$
Hence remainder $=1$
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