Thermodynamics Question 2

Question 2 - 2024 (01 Feb Shift 2)

For a certain reaction at $300 K, K=10$, then $\Delta G^{\circ}$ for the same reaction is $\times 10^{-1} kJ mol^{-1}$. (Given $R=8.314 JK^{-1} mol^{-1}$ )

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Answer (57)

Solution

$\Delta G^{\circ}=-RT \ell nK$

$=-8.314 \times 300 \ln (10)$

$=5744.14 J / mole$

$=57.44 \times 10^{-1} kJ / mole$