Thermodynamics C Question 2
Question 2 - 2024 (01 Feb Shift 2)
For a certain reaction at $300 \mathrm{~K}, \mathrm{~K}=10$, then $\Delta \mathrm{G}^{\circ}$ for the same reaction is $\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}$. (Given $\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
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Answer (57)
Solution
$\Delta \mathrm{G}^{\circ}=-\mathrm{RT} \ell \mathrm{nK}$
$=-8.314 \times 300 \ln (10)$
$=5744.14 \mathrm{~J} / \mathrm{mole}$
$=57.44 \times 10^{-1} \mathrm{~kJ} / \mathrm{mole}$
