The electronic configuration for Neodymium is:
[Atomic Number for Neodymium 60]
(1) $[Xe] 4 f^{4} 6 s^{2}$
(2) $[Xe] 5 f^{4} 7 s^{2}$
(3) $[Xe] 4 f^{6} 6 s^{2}$
(4) $[Xe] 4 f^{1} 5 d^{1} 6 s^{2}$
Electronic configuration of $Nd(Z=60)$ is; $[Xe] 4 f^{4} 6 s^{2}$
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