Structure Of Atom Question 5
Question 5 - 2024 (27 Jan Shift 1)
The electronic configuration for Neodymium is:
[Atomic Number for Neodymium 60]
(1) $[\mathrm{Xe}] 4 \mathrm{f}^{4} 6 \mathrm{~s}^{2}$
(2) $[\mathrm{Xe}] 5 \mathrm{f}^{4} 7 \mathrm{~s}^{2}$
(3) $[\mathrm{Xe}] 4 \mathrm{f}^{6} 6 \mathrm{~s}^{2}$
(4) $[\mathrm{Xe}] 4 \mathrm{f}^{1} 5 \mathrm{~d}^{1} 6 \mathrm{~s}^{2}$
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Answer (1)
Solution
Electronic configuration of $\mathrm{Nd}(\mathrm{Z}=60)$ is; $[\mathrm{Xe}] 4 \mathrm{f}^{4} 6 \mathrm{~s}^{2}$
