$K _a$ for $CH _3 COOH$ is $1.8 \times 10^{-5}$ and $K _b$ for $NH _4 OH$ is $1.8 \times 10^{-5}$. The $pH$ of ammonium acetate solution will be
$pH=\frac{pK _w+pK _a-pK _b}{2}$
$pK _a=pK _b$
$\Rightarrow pH=\frac{pK _w}{2}=7$
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