Chemical Equilibrium Question 1
Question 1 - 2024 (29 Jan Shift 1)
For the reaction $N _2 O _4(g) \rightleftharpoons 2 NO _2(g), K _p=0.492$ atm at $300 K . K _c$ for the reaction at same temperature is ________ $\times 10^{-2}$.
(Given : $R=0.082 L atm mol^{-1} K^{-1}$ )
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Answer (2)
Solution
$K _P=K _C \cdot(RT)^{\Delta n _g}$
$\Delta n _g=1$
$\Rightarrow K _c=\frac{K _P}{RT}=\frac{0.492}{0.082 \times 300}=2 \times 10^{-2}$
