Chemical Equilibrium Question 1
Question 1 - 2024 (29 Jan Shift 1)
For the reaction $\mathrm{N}{2} \mathrm{O}{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}{2}(\mathrm{~g}), \mathrm{K}{\mathrm{p}}=0.492$ atm at $300 \mathrm{~K} . \mathrm{K}_{\mathrm{c}}$ for the reaction at same temperature is ________ $\times 10^{-2}$.
(Given : $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ )
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Answer (2)
Solution
$\mathrm{K}{\mathrm{P}}=\mathrm{K}{\mathrm{C}} \cdot(\mathrm{RT})^{\Delta \mathrm{n}_{\mathrm{g}}}$
$\Delta \mathrm{n}_{\mathrm{g}}=1$
$\Rightarrow \mathrm{K}{\mathrm{c}}=\frac{\mathrm{K}{\mathrm{P}}}{\mathrm{RT}}=\frac{0.492}{0.082 \times 300}=2 \times 10^{-2}$
