Electrostatics Question 8
Question 8 - 29 January - Shift 1
Ratio of thermal energy released in two resistor $R$ and 3R connected in parallel in an electric circuit is :
(1) $3: 1$
(2) $1: 1$
(3) $1: 3$
(4) $1: 27$
Show Answer
Answer: (1)
Solution:
$H=\frac{V^{2}}{R} \times t$
$V^{2} t$
$\frac{H_1}{H_2}=\frac{R}{V^{2} t}=3: 1$
3R