Electrostatics Question 8

Question 8 - 29 January - Shift 1

Ratio of thermal energy released in two resistor $R$ and 3R connected in parallel in an electric circuit is :

(1) $3: 1$

(2) $1: 1$

(3) $1: 3$

(4) $1: 27$

Show Answer

Answer: (1)

Solution:

$H=\frac{V^{2}}{R} \times t$

$V^{2} t$

$\frac{H_1}{H_2}=\frac{R}{V^{2} t}=3: 1$

3R