Electrostatics Question 7

Question 7 - 29 January - Shift 1

In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ’ $S$ ’ having area of $4 L^{2}$. The flux through the opposite surface to ’ $S$ ’ is given by

(1) $\frac{q}{12 \varepsilon_0}$

(2) $\frac{q}{3 \varepsilon_0}$

(3) $\frac{q}{2 \varepsilon_0}$

(4) $\frac{q}{6 \varepsilon_0}$

Show Answer

Answer: (4)

Solution:

Formula: Electric Flux

$\phi=\frac{Q / \varepsilon_0}{6}$

Flux passing through shaded face $=\frac{q}{6 \varepsilon_0}$