Electrostatics Question 7
Question 7 - 29 January - Shift 1
In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ’ $S$ ’ having area of $4 L^{2}$. The flux through the opposite surface to ’ $S$ ’ is given by
(1) $\frac{q}{12 \varepsilon_0}$
(2) $\frac{q}{3 \varepsilon_0}$
(3) $\frac{q}{2 \varepsilon_0}$
(4) $\frac{q}{6 \varepsilon_0}$
Show Answer
Answer: (4)
Solution:
Formula: Electric Flux
$\phi=\frac{Q / \varepsilon_0}{6}$
Flux passing through shaded face $=\frac{q}{6 \varepsilon_0}$
