Electromagnetic Induction Question 3

Question 3 - 25 January - Shift 2

A wire of length $1 m$ moving with velocity $8 m / s$ at right angles to a magnetic field of $2 T$. The magnitude of induced emf, between the ends of wire will be

(1) $20 V$

(2) $8 V$

(3) $12 V$

(4) $16 V$

Show Answer

Answer: (4)

Solution:

Induced emf across the ends $=Bv \ell$

$=2 \times 8 \times 1=16 V$