Electromagnetic Induction Question 3
Question 3 - 25 January - Shift 2
A wire of length $1 m$ moving with velocity $8 m / s$ at right angles to a magnetic field of $2 T$. The magnitude of induced emf, between the ends of wire will be
(1) $20 V$
(2) $8 V$
(3) $12 V$
(4) $16 V$
Show Answer
Answer: (4)
Solution:
Induced emf across the ends $=Bv \ell$
$=2 \times 8 \times 1=16 V$