Thermodynamics Question 7

Question 7 - 31 January - Shift 1

The enthalpy change for the conversion of $\frac{1}{2} Cl_2$ (g) to $Cl^{-}$(aq) is (-)_________

$kJ mol^{-1}$ (Nearest integer)

Given : $\Delta _{\text{dis }} H _{Cl _{2(g)}}^{o}=240 kJmol^{-1}$.

$\Delta _{eg} H _{Cl _{(g)}}^{o}=-350 kJmol^{-1}$,

$\Delta _{\text{hyd }} H _{Cl _{(g)}^{-}}^{o}=-380 kJmol^{-1}$

Show Answer

Answer: (610)

Solution:

Formula: Enthalpy Change

$\frac{1}{2} Cl _{2(g)} \to Cl _{\text{(g) }} \to Cl _{\text{(g) }}^{-} \to Cl _{\text{(aq.) }}^{-}$

$\Delta H^{o}=\frac{1}{2} \times 240+(-350)+(-380)$

$=-610$ ans.