Thermodynamics Question 7
Question 7 - 31 January - Shift 1
The enthalpy change for the conversion of $\frac{1}{2} Cl_2$ (g) to $Cl^{-}$(aq) is (-)
$kJ mol^{-1}$ (Nearest integer)
Given : $\Delta _{\text{dis }} H _{Cl _{2(g)}}^{o}=240 kJmol^{-1}$.
$\Delta _{eg} H _{Cl _{(g)}}^{o}=-350 kJmol^{-1}$,
$\Delta _{\text{hyd }} H _{Cl _{(g)}^{-}}^{o}=-380 kJmol^{-1}$
Show Answer
Answer: (610)
Solution:
Formula: Enthalpy Change
$\frac{1}{2} Cl _{2(g)} \to Cl _{\text{(g) }} \to Cl _{\text{(g) }}^{-} \to Cl _{\text{(aq.) }}^{-}$
$\Delta H^{o}=\frac{1}{2} \times 240+(-350)+(-380)$
$=-610$ ans.
