Optics 6 Question 4

5. In an interference experiment, the ratio of amplitudes of coherent waves is a1a2=13. The ratio of maximum and minimum intensities of fringes will be

(a) 2

(b) 18

(c) 4

(d) 9

(2019 Main, 8 April I)

Show Answer

Answer:

Correct Answer: 5. (c)

Solution:

  1. In Young’s double slit experiment, ratio of maxima and minima intensity is given by

As, intensity (I)[amplitude(a)]2

I1I2=(a1a2)2=(13)2=19

So, ImaxImin=(13+1131)2=4:1



NCERT Chapter Video Solution

Dual Pane