Optics 6 Question 4

5. In an interference experiment, the ratio of amplitudes of coherent waves is a1a2=13. The ratio of maximum and minimum intensities of fringes will be

(a) 2

(b) 18

(c) 4

(d) 9

(2019 Main, 8 April I)

Show Answer

Solution:

  1. In Young’s double slit experiment, ratio of maxima and minima intensity is given by

As, intensity (I)[amplitude(a)]2

I1I2=a1a22=132=19

So, ImaxImin=13+1131=4:1



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक