Optics 3 Question 27
27. Four combinations of two thin lenses are given in Column I.The radius of curvature of all curved surfaces is $r$ and the refractive index of all the lenses is 1.5. Match lens combinations in Column I with their focal length in Column II and select the correct answer using the codes given below the lists.
(2014 Adv.)
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Answer:
Correct Answer: 27. (A) $\rightarrow$ p; (B) $\rightarrow s$; (C) $\rightarrow r$; (D) $\rightarrow p$
- (P) $\frac{1}{f}=\frac{3}{2}-1 \frac{1}{r}+\frac{1}{r}=\frac{1}{r} \Rightarrow f=r$
$\Rightarrow \quad \frac{1}{f _{eq}}=\frac{1}{f}+\frac{1}{f}=\frac{2}{r} \Rightarrow f _{eq}=\frac{r}{2}$
(Q) $\frac{1}{f}=\frac{3}{2}-1 \frac{1}{r} \Rightarrow f=2 r$
$\Rightarrow \frac{1}{\varphi}+\frac{1}{\varphi}=\frac{2}{\varphi}=\frac{1}{\rho} \Rightarrow f _{\text {eq }}=r$
(R) $\frac{1}{f}=\frac{3}{2}-1 \quad-\frac{1}{r}=-\frac{1}{2 r} \Rightarrow f=-2 r$
$\Rightarrow \frac{1}{f _{eq}}=\frac{1}{f}+\frac{1}{f}=-\frac{2}{2 r} \Rightarrow f _{eq}=-r$
(S) $\Rightarrow \frac{1}{f _{\text {eq }}}=\frac{1}{r}+\frac{1}{-2 r}=\frac{1}{2 r} \Rightarrow f _{\text {eq }}=2 r$