Modern Physics 7 Question 24

25. If the magnetic field of a plane electromagnetic wave is given by

$B=100 \times 10^{-6} \sin 2 \pi \times 2 \times 10^{15} t-\frac{x}{c}$,

then the maximum electric field associated with it is (Take, the speed of light $=3 \times 10^{8} m / s$ )

(Main 2019, 10 Jan I)

(a) $6 \times 10^{4} N / C$

(b) $4 \times 10^{4} N / C$

(c) $3 \times 10^{4} N / C$

(d) $4.5 \times 10^{4} N / C$

Show Answer

Solution:

  1. Given, instantaneous value of magnetic field

$$ B=100 \times 10^{-6} \sin 2 \pi \times 2 \times 10^{15} t-\frac{x}{c} $$

and speed of light, $c=3 \times 10^{8} ms^{-1}$

For an electromagnetic wave,

$$ E _{\max }=B _{\max } \times c $$

where, $E _{\max }=$ maximum value of the electric field.

We get, $E _{\max }=100 \times 10^{-6} \times 3 \times 10^{8}=3 \times 10^{4} \frac{N}{C}$



NCERT Chapter Video Solution

Dual Pane