Modern Physics 5 Question 16

17. The equation;

$4{ } _1^{1} H \rightarrow{ } _2^{4} He^{2+}+2 e^{-}+26 MeV$ represents $\quad(1983,1 M)$

(a) $\beta$-decay

(b) $\gamma$-decay

(c) fusion

(d) fission

Passage Based Questions

Passage 1

The mass of a nucleus ${ } _Z^{A} X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m _1$ and $m _2$ only if $\left(m _1+m _2\right)<M$. Also two light nuclei of masses $m _3$ and $m _4$ can undergo complete fusion and form a heavy nucleus of mass $M^{\prime}$ only if $\left(m _3+m _4\right)>M^{\prime}$. The masses of some neutral atoms are given in the table below

(2013 Adv.)

${ } _1^{1} H$ $1.007825 u$ ${ } _1^{2} H$ $2.014102 u$
${ } _3^{6} Li$ $6.01513 u$ ${ } _3^{7} Li$ $7.016004 u$
${ } _{64}^{152} Gd$ $151.919803 u$ ${ } _{82}^{206} Pb$ $205.974455 u$
${ } _1^{3} H$ $3.016050 u$ ${ } _2^{4} He$ $4.002603 u$
${ } _{30}^{70} Zn$ $69.925325 u$ ${ } _{34}^{82} Se$ $81.916709 u$
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Answer:

Correct Answer: 17. (a)

Solution:

  1. During fusion process two or more lighter nuclei combine to form a heavy nucleus.


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