Modern Physics 5 Question 16
17. The equation;
$4{ } _1^{1} H \rightarrow{ } _2^{4} He^{2+}+2 e^{-}+26 MeV$ represents $\quad(1983,1 M)$
(a) $\beta$-decay
(b) $\gamma$-decay
(c) fusion
(d) fission
Passage Based Questions
Passage 1
The mass of a nucleus ${ } _Z^{A} X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m _1$ and $m _2$ only if $\left(m _1+m _2\right)<M$. Also two light nuclei of masses $m _3$ and $m _4$ can undergo complete fusion and form a heavy nucleus of mass $M^{\prime}$ only if $\left(m _3+m _4\right)>M^{\prime}$. The masses of some neutral atoms are given in the table below
(2013 Adv.)
| ${ } _1^{1} H$ | $1.007825 u$ | ${ } _1^{2} H$ | $2.014102 u$ |
|---|---|---|---|
| ${ } _3^{6} Li$ | $6.01513 u$ | ${ } _3^{7} Li$ | $7.016004 u$ |
| ${ } _{64}^{152} Gd$ | $151.919803 u$ | ${ } _{82}^{206} Pb$ | $205.974455 u$ |
| ${ } _1^{3} H$ | $3.016050 u$ | ${ } _2^{4} He$ | $4.002603 u$ |
| ${ } _{30}^{70} Zn$ | $69.925325 u$ | ${ } _{34}^{82} Se$ | $81.916709 u$ |
Show Answer
Answer:
Correct Answer: 17. (a)
Solution:
- During fusion process two or more lighter nuclei combine to form a heavy nucleus.
