Modern Physics 2 Question 27

26. The work functions of silver and sodium are 4.6 and $2.3 eV$, respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is

(2013 Adv.)

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Solution:

  1. $e V _0=h f-W$

$\therefore \quad V _0=\frac{h}{e} f-\frac{W}{e}$

$V _0$ versus $f$ graph is a straight line with slope $=\frac{h}{e}=a$ universal constant. Therefore, the ratio of two slopes should be 1 .



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