Modern Physics 2 Question 27
26. The work functions of silver and sodium are 4.6 and $2.3 eV$, respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is
(2013 Adv.)
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Solution:
- $e V _0=h f-W$
$\therefore \quad V _0=\frac{h}{e} f-\frac{W}{e}$
$V _0$ versus $f$ graph is a straight line with slope $=\frac{h}{e}=a$ universal constant. Therefore, the ratio of two slopes should be 1 .
