Magnetics 4 Question 6

7. A loop carrying current I lies in the xy plane as shown in the figure. The unit vector k^ is coming out of the plane of the paper. The magnetic moment of the current loop is

(2012)

(a) a2Ik^

(b) π2+1a2Ik^

(c) π2+1a2Ik^

(d) (2π+1)a2Ik^

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Answer:

Correct Answer: 7. (b)

Solution:

  1. Area of the given loop is

A= (area of two circles of radius a2 and area of a square of side a )

=2πa22+a2=π2+1a2|M|=IA=π2+1a2I

From screw law direction of M is outwards or in positive z-direction.

M=π2+1a2Ik^



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