Heat and Thermodynamics 5 Question 20

21. An ideal gas expands isothermally from a volume $V _1$ to $V _2$ and then compressed to original volume $V _1$ adiabatically. Initial pressure is $p _1$ and final pressure is $p _3$. The total work done is $W$. Then,

(2004, 2M)

(a) $p _3>p _1, W>0$

(b) $p _3<p _1, W<0$

(c) $p _3>p _1, W<0$

(d) $p _3=p _1, W=0$

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Answer:

Correct Answer: 21. (c)

Solution:

  1. Slope of adiabatic process at a given state $(p, V, T)$ is more than the slope of isothermal process. The corresponding $p-V$ graph for the two processes is as shown in figure.

In the graph, $A B$ is isothermal and $B C$ is adiabatic.

$$ W _{A B}=\text { positive (as volume is increasing) } $$

and $W _{B C}=$ negative (as volume is decreasing) plus,

$\left|W _{B C}\right|>\left|W _{A B}\right|$, as area under $p$ - $V$ graph gives the work done.

Hence, $\quad W _{A B}+W _{B C}=W<0$

From the graph itself, it is clear that $p _3>p _1$.

NOTE

At point $B$, slope of adiabatic (process $B C$ ) is greater than the slope of isothermal (process $A B$ ).



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