Heat and Thermodynamics 4 Question 30
32. At room temperature, the rms speed of the molecules of a certain diatomic gas is found to be $1930 m / s$. The gas is
(a) $H _2$
(b) $F _2$
(c) $O _2$
(d) $Cl _2$
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Answer:
Correct Answer: 32. (a)
Solution:
- $v _{rms}=\sqrt{\frac{3 R T}{M}}$
Room temperature $T \approx 300 K$
$$ \begin{aligned} & \therefore \quad 1930=\sqrt{\frac{3 \times 8.31 \times 10^{3} \times 300}{M}} \\ & \therefore \quad M=2.0 g / mol \text { or the gas is } H _2 \text {. } \end{aligned} $$
