SATHEE: Electrostatics 5 Question 26

Electrostatics 5 Question 26

28. Two identical capacitors, have the same capacitance $C$ . One of them is charged to potential $V_{1}$ and the other to $V_{2}$ . Likely charged plates are then connected. Then, the decrease in energy of the combined system is

(a) $\frac{1}{4} C (V_{1}^{2} - V_{2}^{2})$

(b) $\frac{1}{4} C (V_{1}^{2} + V_{2}^{2})$

(d) $\frac{1}{4} C {(V_{1} + V_{2})}^{2}$

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Answer:

Correct Answer: 28. (c)

Solution:

$Δ U =$ decrease in potential energy

$\begin{aligned} = U_{i} - U_{f} \\ = \frac{1}{2} C (V_{1}^{2} + V_{2}^{2}) - \frac{1}{2} (2 C) \frac{V_{1} + V_{2}}{2} \\ = \frac{1}{4} C {(V_{1} - V_{2})}^{2} \end{aligned}$

Electrostatics 5 Question 26

28. Two identical capacitors, have the same capacitance $C$ . One of them is charged to potential $V_{1}$ and the other to $V_{2}$ . Likely charged plates are then connected. Then, the decrease in energy of the combined system is

Answer:

Solution:

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Electrostatics 5 Question 26

28. Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. Likely charged plates are then connected. Then, the decrease in energy of the combined system is

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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28. Two identical capacitors, have the same capacitance $C$ . One of them is charged to potential $V_{1}$ and the other to $V_{2}$ . Likely charged plates are then connected. Then, the decrease in energy of the combined system is