Electrostatics 5 Question 20

22. In the given circuit, charge Q2 on the 2μF capacitor changes as C is varied from 1μF to 3μF.Q2 as a function of C is given properly by (figures are drawn schematically and are not to scale)

(2015 Main)

(a)

(b)

(c)

(d)

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Answer:

Correct Answer: 22. (a)

Solution:

  1. Resultant of 1μF and 2μF is 3μF. Now in series, potential difference distributes in inverse ratio of capacity.

V3μFVc=c3 or V3μF=cc+3E

This is also the potential difference across 2μF.

Q2=(2μF)(V2μF) or Q2=2cEc+3=21+3cE

From this expression of Q2, we can see that Q2 will increase with increase in the value of c (but not linearly). Therefore, only options (a) and (b) may be correct.

Further, ddc(Q2)=2E(c+3)c(c+3)2=6E(c+3)2

= Slope of Q2 verus c graph

i.e. slope of Q2 versus c graph decreases with increase in the value of c. Hence, the correct graph is (a).



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