SATHEE: Electromagnetic Induction and Alternating Current 7 Question 18

Electromagnetic Induction and Alternating Current 7 Question 18

####18. In the method using the transformers, assume that the ratio of the number of turns in the primary to that in the secondary in the step-up transformer is $1 : 10$ . If the power to the consumers has to be supplied at $200 V$ , the ratio of the number of turns in the primary to that in the secondary in the step-down transformer is

(a) $200 : 1$

(b) $150 : 1$

(c) $100 : 1$

(d) $50 : 1$

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Answer:

Correct Answer: 18. (a)

Solution:

During step-up, $\frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$ or $\frac{1}{10} = \frac{4000}{V_{s}}$

or $V_{s} = 40000 V$

In step down transformer,

$\frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}} = \frac{40000}{200} = \frac{200}{1}$

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Electromagnetic Induction and Alternating Current 7 Question 18

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