Theory of Equations 4 Question 2

2. Consider the quadratic equation, (c5)x22cx+(c4) =0,c5. Let S be the set of all integral values of c for which one root of the equation lies in the interval (0,2) and its other root lies in the interval (2,3). Then, the number of elements in S is

(2019 Main, 10 Jan I)

(a) 11

(b) 10

(c) 12

(d) 18

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Answer:

Correct Answer: 2. (a)

Solution:

  1. Let f(x)=(c5)x22cx+(c4)=0.

Then, according to problem, the graph of y=f(x) will be either of the two ways, shown below.

In both cases f(0).f(2)<0 and f(2)f(3)<0

Now, consider

f(0)f(2)<0

(c4)[4(c5)4c+(c4)]<0

(c4)(c24)<0

c(4,24)

Similarly, f(2)f(3)<0

[4(c5)4c+(c4)]

$ \begin{aligned} & {[9(c-5)-6 c+(c-4)]<0} \ & \Rightarrow \quad(c-24)(4 c-49)<0 \ & \begin{array}{lll}

  • & - & + \ \hline 49 / 4 & 24 \end{array} \ & \Rightarrow \quad c \in \frac{49}{4}, 24 \end{aligned} $

From Eqs. (i) and (ii), we get

c494,24

Integral values of c are 13,14 , 23. Thus, 11 integral values of c are possible.



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