Theory of Equations 1 Question 40

41. If 2+i3 is a root of the equation x2+px+q=0, where p and q are real, then (p,q)=(…,…).

(1982, 2M)

Show Answer

Answer:

Correct Answer: 41. (-4,7)

Solution:

  1. If 2+i3 is one of the root of x2+px+q=0. Then, other root is 2−i3.

⇒−p=2+i3+2−i3=4

 and q=(2+i3)(2−i3)=7

⇒(p,q)=(−4,7)

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