Straight Line and Pair of Straight Lines 1 Question 69

69. One side of a rectangle lies along the line 4x+7y+5=0. Two of its vertices are (3,1) and (1,1). Find the equations of the other three sides. (1978, 3M)

Integer Answer Type Question

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Answer:

Correct Answer: 69. 6 sq units

Solution:

  1. Since, the side AB is perpendicular to AD.

Its equation is of the form 7x4y+λ=0

Since, it passes through (3,1).

7(3)4(1)+λ=0.λ=25

Equation of AB is

7x4y+25=0

Now, BC is parallel to AD. Therefore, its equation is

4x+7y+λ=0

Since, it passes through (1,1).

4(1)+7(1)+λ=0λ=11

Equation of BC is 4x+7y11=0

Now, equation of DC is 7x4y+λ=0

7(1)4(1)+λ=0λ=37x4y3=0



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