Straight Line and Pair of Straight Lines 1 Question 58

58. Straight lines 3x+4y=5 and 4x3y=15 intersect at the point A. Points B and C are chosen on these two lines such that AB=AC. Determine the possible equations of the line BC passing through the point (1,2).

(1990,4 M)

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Solution:

  1. Let m1 and m2 be the slopes of the lines 3x+4y=5 and 4x3y=15, respectively.

Then, m1=34 and m2=43

Clearly, m1m2=1. So, lines AB and AC are at right angle. Thus, the ABC is a right angled isosceles triangle.

Hence, the line BC through (1,2) will make an angle of 45 with the given lines. So, the possible equations of BC are

(y2)=m±tan451mtan45(x1)

where, m= slope of AB=34

(y2)=34±1134(x1)(y2)=3±44±3(x1)(y2)=17(x1) and (y2)=7(x1)x7y+13=0 and 7x+y9=0



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