Straight Line and Pair of Straight Lines 1 Question 56

56.

Determine all values of α for which the point (α,α2) lies inside the triangles formed by the lines 2x+3y1=0,

x+2y3=0,5x6y1=0

(1992, 6M)

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Answer:

Correct Answer: 56. (32<α<112<α<1)

Solution:

  1. Given lines are 2x+3y1=0 …….(i)

x+2y3=0 …….(ii)

5x6y1=0 …….(iii)

On solving Eqs. (i), (ii) and (iii), we get the vertices of a triangle are A(7,5),B(13,19) and C(54,78).

Let P(α,α2) be a point inside the ABC. Since, A and P are on the same side of 5x6y1=0, both 5(7)6(5)1 and 5α6α21 must have the same sign, therefore

5α6α21<06α25α+1>0(3α1)(2α1)>0α<13 or α>12.(iv)

Also, since P(α,α2) and C(54,78) lie on the same side of 2x+3y1=0, therefore both 2(54)+3(78)1 and 2α+3α21 must have the same sign.

Therefore,

2α+3α21>0

(α+1)α13>0α<1α>1/3.(v)

and lastly (13,19) and P(α,α2) lie on the same side of the line therefore, 13+2(19)3 and α+2α23 must have the same sign.

Therefore, 2α2+α3<0

2α(α1)+3(α1)<0(2α+3)(α1)<023<α<1

On solving Eqs. (i), (ii) and (iii), we get the common answer is 32<α<112<α<1.



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