Straight Line and Pair of Straight Lines 1 Question 53

53.

For points P=(x1,y1) and Q=(x2,y2) of the coordinate plane, a new distance d(P,Q) is defined by d(P,Q)=|x1x2|+|y1y2|.

Let O=(0,0) and A=(3,2). Prove that the set of points in the first quadrant which are equidistant (with respect to the new distance) from O and A consists of the union of a line segment of finite length and an infinite ray. Sketch this set in a labelled diagram.

(2000,10M)

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Solution:

  1. d:(P,Q)=|x1x2|+|y1y2|.

It is new method of representing distance between two points P and Q and in future very important in coordinate geometry.

Now, let P(x,y) be any pont in the first quadrant. We have

d(P,0) =|x0|+|y0|=|x|+|y|=x+y

[x,y>0]

d(P,A) =|X3|+|Y2| [given]

d(P,0) =d(P,A) [given]

x+y =|x3|+|y2| (i)

Case I When 0<x<3,0<y<2

Case I When 0<x<3,0<y<2

In this case, Eq. (i) becomes

x+y=3x+2y

2x+2y=5 or x+y=5/2

Case II When 0<x<3,y2

Now, Eq. (i) becomes

x+y=3x+y22x=1x=1/2

Case III When x3,0<y<2

Now, Eq. (i) becomes

x+y=x3+2y2y=1 or y=1/2

Hence, no solution.

Case IV When x3,y2

In this case, case I changes to

x+y=x3+y20=5

which is not possible.

Hence, the solution set is

(x,y)x=12,y2(x,y)

x+y=5/2,0<x<3,0<y>2

The graph is given in adjoining figure.



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