Permutations and Combinations 5 Question 1

1. Number of divisors of the form (4n+2),n0 of the integer 240 is

(1998, 2M)

(a) 4

(b) 8

(c) 10

(d) 3

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Answer:

Correct Answer: 1. (a)

Solution:

  1. Since, 240=2435

Total number of divisors =(4+1)(2)(2)=20

Out of these 2, 6,10 , and 30 are of the form 4n+2.



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