Permutations and Combinations 5 Question 1
1. Number of divisors of the form $(4 n+2), n \geq 0$ of the integer 240 is
(1998, 2M)
(a) 4
(b) 8
(c) 10
(d) 3
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Answer:
Correct Answer: 1. (a)
Solution:
- Since, $240=2^{4} \cdot 3 \cdot 5$
$\therefore$ Total number of divisors $=(4+1)(2)(2)=20$
Out of these 2, 6,10 , and 30 are of the form $4 n+2$.
