Permutations and Combinations 1 Question 5

5. How many different nine-digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions? (2000,2M)

(a) 16

(b) 36

(c) 60

(d) 180

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Answer:

Correct Answer: 5. (c)

Solution:

  1. XXXXX. The four digits 3,3,5,5 can be arranged at ( ) places in 4!2!2!=6 ways.

The five digits 2,2,8,8,8 can be arranged at (X) places in 5!2!3! ways =10 ways.

Total number of arrangements =6×10=60

[since, events A and B are independent, therefore AB=A×B]



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